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English(EN) How Unbalanced Must a Latin Rectangle Be?

新研究量化拉丁方阵的不平衡性

本文探讨了拉丁方阵的平衡概念,将其视为网格中的点,并使用L1度量来衡量其不平衡性。研究人员开发了一种模拟退火方法,该方法改进了现有的非方形矩形基准,并为先前找到的最小不平衡值的最优性提供了计算机辅助证明。该研究还建立了最小不平衡的渐近界限,并研究了完美平衡的条件,所有报告的矩形均使用Lean 4编程语言及其Mathlib库进行了验证。 AI

排序理由 该集群包含一篇详细介绍新数学研究的学术论文。[lever_c_demoted from research: ic=1 ai=0.1]

在 arXiv cs.AI 阅读 →

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新研究量化拉丁方阵的不平衡性

本文如何被排名

Signal score
2 / 100
Composite score across the factors below. Higher = stronger signal that this story matters right now.
Newsworthiness bucket
Tool
该集群包含一篇详细介绍新数学研究的学术论文。[lever_c_demoted from research: ic=1 ai=0.1]
Source corroboration
Single-source cluster
Only one publisher covered this so far. Single-source stories can still rank when the publisher is high-authority, but they lack cross-source corroboration.
Topics
paper, other
Editorial topic classification. Feeds into how the story surfaces on /topic/<slug> hub pages and into the per-entity coverage mix.
AI-industry relevance
Low
Off-topic or adjacent — cluster remains reachable but doesn't surface in AI-industry rankings.
Story freshness
Breaking (< 6h)
Fresh story with cross-source coverage still developing. Ranking may shift as more sources report.

完整方法见我们的编辑标准。

报道来源 [1]

  1. arXiv cs.AI TIER_1 English(EN) · Zhengyu Li, Vijay Ganesh ·

    拉丁矩形必须有多么不平衡?

    arXiv:2611.06003v1 Announce Type: cross Abstract: We view a $k\times n$ Latin rectangle as $n$ points in the grid $[n]^k$. Each symbol gives one point, whose coordinates are the columns it occupies. The rectangle is balanced when these points are pairwise equidistant in the $\ell…