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JavaScript's Array.sort() bug: Numbers > 9 sort incorrectly

By PulseAugur Editorial · [1 sources] ·

JavaScript's default Array.sort() method can lead to unexpected ordering when sorting numbers, particularly those with different numbers of digits. This is because the method converts elements to strings and compares them character by character. For instance, '100' sorts before '21' because '2' comes before '3' in string comparison, even though 100 is numerically larger than 21. This behavior can cause significant ordering issues, even in arrays that are initially sorted or contain simple sequences like multiples of a number. The recommended solution is to always provide a compare function, such as (a, b) => a - b, to ensure numerical sorting. AI

RANK_REASON The item describes a common programming bug and its solution.

Read on dev.to — Claude Code tag →

AI-generated summary · Google Gemini · from 1 sources. How we write summaries →

JavaScript's Array.sort() bug: Numbers > 9 sort incorrectly

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  1. dev.to — Claude Code tag TIER_1 English(EN) · RAXXO Studios ·

    The Array.sort() Bug Only Numbers Above 9 Trigger

    <ul> <li><p>Array.sort() with no compare function sorted [11, 22, 110] as [11, 110, 22] in my test</p></li> <li><p>A 20-item array of multiples of 11 came back with 9 of them out of numeric order</p></li> <li><p>A random 10,000-number array had 89 adjacent pairs still out of orde…

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