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ChatGPT Luna 5.6 chatbot costs $1.04 for 3.7M tokens

A user shared their experience running a chatbot powered by ChatGPT Luna 5.6, reporting that over the past 30 days, 371 requests consumed approximately 3.7 million tokens for a total cost of $1.04. This averages out to about $0.003 per request, demonstrating that operating an AI chatbot can be more cost-effective than commonly believed. AI

IMPACT Demonstrates the low operational cost of running AI chatbots, potentially encouraging wider adoption.

RANK_REASON User-generated report on the cost-effectiveness of using a specific AI model for a chatbot application.

Read on r/OpenAI →

AI-generated summary · Google Gemini · from 1 sources. How we write summaries →

ChatGPT Luna 5.6 chatbot costs $1.04 for 3.7M tokens

How we ranked this

Signal score
1 / 100
Composite score across the factors below. Higher = stronger signal that this story matters right now.
Newsworthiness bucket
Tool
User-generated report on the cost-effectiveness of using a specific AI model for a chatbot application.
Source corroboration
Single-source cluster
Only one publisher covered this so far. Single-source stories can still rank when the publisher is high-authority, but they lack cross-source corroboration.
Topics
product, infra
Editorial topic classification. Feeds into how the story surfaces on /topic/<slug> hub pages and into the per-entity coverage mix.
AI-industry relevance
High
Clearly on-topic for AI-industry coverage.
Story freshness
Same-day
Cluster formed today. Ranking reflects the current source set at time of score.

Full methodology in our editorial standards.

COVERAGE [1]

  1. r/OpenAI TIER_2 English(EN) · /u/Spiritual_Grape3522 ·

    371 AI chatbot requests, 3.7M tokens, $1.04 total (ChatGPT Luna 5.6)

    <table> <tr><td> <a href="https://www.reddit.com/r/OpenAI/comments/1xmojdg/371_ai_chatbot_requests_37m_tokens_104_total/"> <img alt="371 AI chatbot requests, 3.7M tokens, $1.04 total (ChatGPT Luna 5.6)" src="https://preview.redd.it/oxasoszi9dzh1.png?width=640&amp;crop=smart&amp;a…